The method
- Rearrange so the right-hand side is zero. Move every term to the left so you have ax² + bx + c compared with 0.
- Find the critical values. Solve ax² + bx + c = 0 by factorising (or the formula).
- Sketch the graph. When the coefficient of x² is positive, the parabola opens upwards and crosses the x-axis at the critical values.
- Read off the region. “< 0” is the part below the x-axis (between the roots). “> 0” is above (outside the roots, written as two inequalities).
Mistakes that lose marks
- Writing x < 5 and x < −1.5 after finding the roots, instead of thinking about the graph.
- Writing “−1.5 > x > 5”, which no number satisfies. For two regions write “x < −1.5 or x > 5”.
- Using ≤ when the question has < (or the other way round). The roots are included only for ≤ and ≥.
- Dividing both sides by x, which can lose a solution and flips the sign when x is negative.
Six exam-style questions
These are our own questions in the style of the exam, not past-paper questions. In every question x, n and k are real numbers (n an integer in question 4). Try each one, then open the solution.
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EXAM-STYLE Solve x² − 5x + 6 > 0 [3 marks]
Show full solution
- Factorise: (x − 2)(x − 3) > 0
- Critical values: x = 2 and x = 3
- The coefficient of x² is positive, so y = x² − 5x + 6 opens upwards and is above the x-axis outside the roots
- x < 2 or x > 3
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EXAM-STYLE Solve 3x² + 4x − 4 ≤ 0 [3 marks]
Show full solution
- Factorise: (3x − 2)(x + 2) ≤ 0
- Critical values: x = ⅔ and x = −2
- The parabola opens upwards, so it is on or below the x-axis between the roots, roots included
- −2 ≤ x ≤ ⅔
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EXAM-STYLE Solve x² < 4x + 12 [3 marks]
Show full solution
- Rearrange so the right-hand side is zero: x² − 4x − 12 < 0
- Factorise: (x − 6)(x + 2) < 0
- Critical values −2 and 6; the parabola is below the x-axis between them
- −2 < x < 6
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EXAM-STYLE Find all the integers n that satisfy n² − n − 20 < 0 [3 marks]
Show full solution
- Factorise: (n − 5)(n + 4) < 0, so −4 < n < 5
- The inequality is strict, so −4 and 5 are not included
- n = −3, −2, −1, 0, 1, 2, 3, 4 (8 integers)
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EXAM-STYLE Solve 2x² + 3x > 5 [3 marks]
Show full solution
- Rearrange so the right-hand side is zero: 2x² + 3x − 5 > 0
- Factorise: (2x + 5)(x − 1) > 0, critical values −5/2 and 1
- The parabola opens upwards, so it is above the x-axis outside the roots
- x < −5/2 or x > 1
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EXAM-STYLE The equation x² + kx + 9 = 0 has two distinct real roots. Find the set of possible values of k. (Additional / Further Maths) [4 marks]
Show full solution
- Two distinct real roots means the discriminant is positive: b² − 4ac > 0
- k² − 4(1)(9) > 0, so k² − 36 > 0
- (k − 6)(k + 6) > 0, critical values ±6
- k < −6 or k > 6
Where this is in the syllabus
Quadratic inequalities appear in Cambridge IGCSE Mathematics 0580 (Extended), Pearson Edexcel International GCSE Mathematics A 4MA1 (Higher) and GCSE Higher tier. For the official specification and past papers, use the board’s own website: Cambridge 0580 and Edexcel 4MA1.